In: Chemistry
write the oxidation reaction,the reduction reaction,
and the cell reaction for the system below:
Pt l H2 (g,p )l HCl (0,030 mol /kg) l AgCl l Ag ,
AgCl(s) + e− | ⇌ | Ag(s) + Cl− | Eo(V) = +0.22233 |
2 H+ + 2 e− | ⇌ | H2(g) | Eo(V) = 0.0000 |
here the one which is having higher reduction potential will get
reduced first.We have Ag having higher reduction potential so it
will get reduced from Ag+ to Ag,whereas H2 will get
oxidized
The oxidation reaction which occurs at the anode would be
H2 2H+(aq) + 2e–
the reduction which occurs at the cathode would be
AgCl(s) + e– Ag(s) +
Cl–
Overall Cell reaction will be
2AgCl(s) + H2(g) 2Ag(s) + 2H+
(aq) + 2Cl– (aq)