In: Statistics and Probability
5. Confidence Intervals Suppose you have the following X: (6, 5, 4, 1, 1). What is the mean of X? What is the Standard deviation of X? What is the Standard Error of X? Calculate the 95% confidence interval for X. Calculate the 99% confidence interval for X.
Solution :
We are given a data of sample size n = 5
6,5,4,1,1
Using this, first we find sample mean()
and sample standard deviation(s).
=
= ( 6 + 5 +.......+ 1 ) / 5
= 3.4
Now ,
s=
Using given data, find Xi -
for each term.Take square for each.Then we can easily find s.
s = 2.302
The Standard Error = (
/
n ) = 2.302 /
5 = 1.0294
Note that, Population standard deviation()
is unknown. So we use t distribution.
Our aim is to construct 95% confidence interval.
c = 0.95
= 1- c = 1- 0.95 = 0.05
/2
= 0.05
2 = 0.025
Also, d.f = n - 1 = 4
=
=
0.025,4
= 2.776
( use t table or t calculator to find this value..)
The margin of error is given by
E = /2,d.f.
* (
/
n )
= 2.776 * (2.302 /
5 )
= 2.858
Now , confidence interval for mean()
is given by:
(
- E ) <
< (
+ E)
( 3.4 - 2.858 ) <
< ( 3.4 + 2.858)
0.542 <
< 6.258
Required 95% confidence interval is ( 0.542 , 6.258 )
Solution:
We are given a data of sample size n = 5
6,5,4,1,1
Using this, first we find sample mean()
and sample standard deviation(s).
=
= ( 6 + 5.......+ 1 ) / 5
= 3.4
Now ,
s=
Using given data, find Xi -
for each term.Take square for each.Then we can easily find s.
s = 2.302
The Standard Error = (
/
n ) = 2.302 /
5 = 1.0294
Note that, Population standard deviation()
is unknown..So we use t distribution.
Our aim is to construct 99% confidence interval.
c = 0.99
= 1 - c = 1 - 0.99 = 0.01
/2
= 0.01
2 = 0.005
Also, d.f = n - 1 = 4
=
=
0.005,4
= 4.604
( use t table or t calculator to find this value..)
The margin of error is given by
E = /2,d.f.
* (
/
n )
= 4.604 * (2.302 /
5 )
= 4.74
Now , confidence interval for mean()
is given by:
(
- E ) <
< (
+ E)
( 3.4 - 4.74 ) <
< ( 3.4 + 4.74 )
-1.34 <
< 8.14
Required 99% confidence interval is ( -1.34 , 8.14 )