In: Statistics and Probability
The distribution of ages of all the employees in Company X follows a normal distribution. The average age is 40 and the standard deviation is 5.
Find the Z-score of a 50 year old employee.
What is the probability that a randomly chosen employee will be younger than 35 years?
What is the probability that a randomly chosen employee will have an age between 35 and 45 years?
What is the probability that a randomly chosen employee will be older than 55 years?
Find the Z-score of a 35 year old employee.
Solution :
Given that ,
mean = = 40
standard deviation = = 5
a.using z score formula
z =(X- ) / = 50 -40 / 5=2
b.
P(X< 35) = P[(X- ) / < (35-40) /5 ]
= P(z < -1)
Using z table
= 0.1587
c.
P(35< x <45 ) = P[(35 - 40) /5 < (x - ) / < (45 - 40) / 5)]
= P(-1< Z <1 )
= P(Z < 1) - P(Z < -1)
Using z table
= 0.8413-0.1587
probability= 0.6826
d.
P(x > 55) = 1 - P(x< 55)
= 1 - P[(x -) / < (55-40) /5 ]
= 1 - P(z <3 )
Using z table
= 1 - 0.9987
= 0.0013
probability= 0.0013
e.
using z score formula
z =(X- ) / = 35 -40 / 5=-1