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Colorblindness is an X-linked recessive trait. Let us assume that a colorblind man has a colorblind...

Colorblindness is an X-linked recessive trait. Let us assume that a colorblind man has a colorblind sister and his mother has normal vision.

What is the genotype, as to color vision, of this man’s mother and of his father?

What kind of color vision will his sons and his daughters have, and in what ratios, if he marries a woman identical in genotype to his mother?

Solutions

Expert Solution

Let the alleles be XC- normal, Xc- colourblindness

the man and his sister are colourblind and his mother has normal vision this shows his mother is heterozygous carrier and his father is colourblind, so genotype of his father is XcY and genotype of his mother is XCXc.

XCXc * XcY

XC Xc
Xc XCXc ( carrier female, with normal vision) XcXc ( colourblind female)
Y XCY ( normal male) XcY ( colourblind male)

it is possible to have colourblind female, colourblind male, carrier female and normal male.

If the man marries a heterozygous female ( female who has the same genotype as that of his mother)

XCXc * XcY

XC Xc
Xc XCXc ( carrier female, with normal vision) XcXc ( colourblind female)
Y XCY ( normal male) XcY ( colourblind male)

the possible genotypes and phenotypes and given in the punnet square.

the ratio is

carrier female: colourblind female: normal male: colourblind male=1:1:1:1

gladiator answered 1 year ago
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