Question

An analysis is interested in testing whether four population have equal means. The following sample data have been collected from population that are assumed to be normally distributed with equal variance:

S1	S2	S3	S4
9	12	8	17
6	16	8	15
11	16	12	17
14	12	7	16
14	9	10	13

You should use the output information in the following manner to answer the question.

1. Calculate the means and standard deviations.

2. Run the appropriate analysis using SPSS. Write the results in the ANOVA table below.

Source of Variation	SS	df	MS	F	Sig. Value
Between Sample
Within Sample
Total

3. Conclusion

4. Write all SPSS Steps:

Answer 1

Solution:

a) SPSS output:

					95% confidence interval for mean
	N	Mean	Std.Deviation	Std.Error	lower bound	upper bound	Minimum	Maximum
1	5	10.80	3.421	1.530	6.55	15.05	6	14
2	5	13.00	3.000	1.342	9.28	16.72	9	16
3	5	9.00	2.000	0.894	6.52	11.48	7	12
4	5	15.60	1.673	0.748	13.52	17.68	13	17

Total

20

12.10

3.493

0.781

10.47

13.73

6

17

b)

	Sum of squares	df	Mean square	F	Sig.
Between Groups	121.800	3	40.600	5.905	0.007
Within Groups	110.000	16	6.875
Total	231.800	19

c) Conclusion:

Use a significance level,

Here p-value is 0.007, which is less than the value of

That is p-value

Therefore, by the rejection rule, the reject the null point hypothesis

Interpretation:

There is sufficient evidence at level of significance  

The four population are all have not equal means.

d)

SPSS Procedure:

Analyze>Compare means>One-Way ANOVA.

In Dependent List: Select Group column.

In Factor: Select Group column.

In Options: Select Descriptives.

Click Ok