In: Statistics and Probability
Show all work for credit (Include original formulas, hypotheses, rejection criteria, decision, and statement in context).
A comparative study of four methods for treating hyperactivity in children was performed in 16 children. After the treatment, hyperactivity was scored on a scale of 1 to 100 where 100 is high hyperactivity. With 99% confidence is there a statistically significant difference among hyperactivity treatments?
Treatments |
|||
1 |
2 |
3 |
4 |
42 |
71 |
41 |
65 |
35 |
78 |
44 |
54 |
40 |
54 |
27 |
43 |
39 |
63 |
39 |
60 |
10 points -Write the null and alternate hypotheses:
Null hypothesis: ________m1=m2=m3=m4______________________________________________________________________________
Alternate Hypothesis: _______differences in the means____________________________________
80 points - Fill in the chart. Show your work for each intermediate calculation. (Staple your work to this page.)
10 points -Are you able to reject the null hypothesis? Show work. Summarize your conclusion.
Null hypothesis : H0 = The treatment means are equal i.e. m1=m2=m3=m4
Alternative Hypothesis : H0 = Atleast one pair of the treatment means are not equal i.e. mi mj
for i j = 1,2,3,4
Here are the calculation results :-
Conceptual Knowledge :
SS between treatments =
MS between treatments = SS between treatments / (k-1)
SS within treatments =
MS within treatments = SS within treatments / (n-k)
F test
MS between treatments / MS within treatments ~ F(k-1, n-k)
764.2292 / 65.2292 = 11.71607 ~ F(3,12) = 2.61
Hence null hypothesis is rejected at 1% level of significance and we conclude that there is significant difference between the treatment means.
Alternatively
The f-ratio value is 11.71607. The p-value is .000705. The result is significant at p < .01. Therefore H0 is rejected at 1% level of significance(99% confidence)