In: Statistics and Probability
Anystate Auto Insurance Company took a random sample of 370
insurance claims paid out during a 1-year period. The average claim
paid was $1535. Assume σ = $254.
Find a 0.90 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
| lower limit | $ | 
| upper limit | $ | 
Find a 0.99 confidence interval for the mean claim payment. (Round
your answers to two decimal places.)
| lower limit | $ | 
| upper limit | 
Solution
Given that,
=1535
= 254
n = 370
a ) At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z
/2
= Z0.05 = 1.645
Margin of error = E = Z
/2*
(
/n)
= 1.645 * (254/ 
370 )
= 21.72
At 90% confidence interval estimate of the population mean is,
- E < 
 < 
 + E
1535 - 21.72 < 
 < 1535 + 21.72
1513.28 < 
 < 1556.72
Lower limit =1513.28
Upper limit = 1556.72
b ) At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z
/2
= Z 0.005 = 2.576
Margin of error = E = Z
/2*
(
/n)
= 2.576 * (254/ 
370 )
= 34.01
At 99% confidence interval estimate of the population mean is,
- E < 
 < 
 + E
1535 - 34.01 < 
 < 1535 + 34.01
1500.99 < 
 < 1569.01
Lower limit =1500.99
Upper limit =1569.01