In: Statistics and Probability
(b) In a tutorial session of AMA1501, there are 11 accounting
students, 6 marketing students and 8 financial service students.
Among these 25 students, a group of 5 students is selected randomly
for the first presentation.
i. How many different groups can be formed?
ii. What is the probability that this group consists of only
accounting students?
iii. What is the probability that this group consists of exactly 2
accounting students and 3 marketing students?
Number of accounting students = 11
Number of marketing students = 6
Number of financial service students = 8
Total number of students = 25
Number students to be selected in the group for the first presentation = 5
i. How many different groups can be formed?
Number of different groups that can be formed = Number of ways of selecting 5 students from a total 25 students
Number of different groups that can be formed = 53130
ii. What is the probability that this group consists of only accounting students
Probability that this group consists of only accounting students
= Number of ways of selecting 5 accounting students from 11 accounting students / Number of ways of selecting 5 students from a total 25 students
Probability that this group consists of only accounting students = 0.008695652
iii. What is the probability that this group consists of exactly 2 accounting students and 3 marketing students
Probability that this group consists of exactly 2 accounting students and 3 marketing students
=[( Number of ways of selecting 2 accounting students from 11 accounting students) x ( Number of ways of selecting 3 marketing students from 6 marketing students)] / [Number of ways of selecting 5 students from a total 25 students]
Probability that this group consists of exactly 2 accounting students and 3 marketing students = 0.020703934