Question

A police department released the numbers of calls for the different days of the week during the month of​ October, as shown in the table to the right. Use a

0.010.01

significance level to test the claim that the different days of the week have the same frequencies of police calls. What is the fundamental error with this​ analysis?

Day nbspDay	Sun	Mon	Tues	Wed	Thurs	Fri	Sat
FrequencyFrequency	159159	207207	229229	246246	177177	215215	232232

Determine the null and alternative hypotheses.

Upper H 0H0​:

▼

At least one day has a different frequency of calls than the other days.

Police calls occur with all different frequencies on the different days of the week.

Police calls occur with the same frequency on the different days of the week.

At least two days have a different frequency of calls than the other days.

Upper H 1H1​:

▼

Police calls occur with the same frequency on the different days of the week.

Police calls occur with all different frequencies on the different days of the week.

At least two days have a different frequency of calls than the other days.

At least one day has a different frequency of calls than the other days.

Calculate the test​ statistic,

chi squaredχ2.

chi squaredχ2equals=nothing

​(Round to three decimal places as​ needed.)

Calculate the​ P-value.

​P-valueequals=nothing

​(Round to four decimal places as​ needed.)

What is the conclusion for this hypothesis​ test?

A.

RejectReject

Upper H 0H0.

There is

sufficientsufficient

evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

B.

Fail to rejectFail to reject

Upper H 0H0.

There is

insufficientinsufficient

evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

C.

Fail to rejectFail to reject

Upper H 0H0.

There is

sufficientsufficient

evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

D.

RejectReject

Upper H 0H0.

There is

insufficientinsufficient

evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

What is the fundamental error with this​ analysis?

A.

Because October has 31​ days, two of the days of the week occur more often than the other days of the week.

B.

Because October has 31​ days, three of the days of the week occur more often than the other days of the week.

C.

Because October has 31​ days, each day of the week occurs the same number of times as the other days of the week.

D.

Because October has 31​ days, one of the days of the week occur more often than the other days of the week.

Answer 1

the null and alternative hypothesis is

H0:Police calls occur with the same frequency on the different days of the week. the null and alternative hypotheses.

Ha:At least two days have a different frequency of calls than the other days.

using minitab>stat>tables >chi square

we have

Chi-Square Goodness-of-Fit Test for Observed Counts in Variable: Frequency

Using category names in Days

Test Contribution
Category Observed Proportion Expected to Chi-Sq
Sun 159 0.142857 209.286 12.0823
Mon 207 0.142857 209.286 0.0250
Tue 229 0.142857 209.286 1.8570
Wed 246 0.142857 209.286 6.4407
Thu 177 0.142857 209.286 4.9806
Fri 215 0.142857 209.286 0.1560
Sat 232 0.142857 209.286 2.4652

N DF Chi-Sq P-Value
1465 6 28.0068 0.000

the test​ statistic,

chi squaredχ2 = 28.007

the​ P-value.= 0.0000

the conclusion for this hypothesis​ test is

A.Reject Ho

There is sufficient evidence to warrant rejection of the claim that the different days of the week have the same frequencies of police calls.

the fundamental error with this​ analysis is

D.Because October has 31​ days, one of the days of the week occur more often than the other days of the week.