Question

 

1.) The National Ambient Air Quality Standard (NAAQS, 1997) for ozone (O₃) is 0.08 ppm(v). Express that standard in Micrograms/Meters³ assuming atmospheric conditions of 1 atm of pressure 22 degrees celsius.

2.) Assume that automobile exhaust gas contains 1% by volume carbon monoxide (CO). If the atmospheric conditions are 0.9 atm and 21 degrees ceslsius.

A.) What is the concentration of CO in ppm(v)?

B.) What is the concentration of CO in mg/m³?

Answer 1

1)   Concentration of O3 = 0.08 ppm(v)  

      1 ppm(v) = 1 ml/L

Concentration of O3 = 0.08 ml/L

1 ml = 10^3 ul    , 1 L = 10^-3 m^3

Concentration of O3 =   0.08*10^3 ul / 10^-3 m^3

                                 = 0.08*10^6

                                = 8*10^4 ul/m^3

                                = 8*10^4 ug/m^3

2)

A) concentration of carbon monoxide (CO) = 1%(v/v)

                    in PPM(v) = %(v/v)*10^3

                                 = 1*1000  

                                 = 1000 ppm

B) concentration of carbon monoxide (CO) = 1000 ml/L                                (1 ppm = 1 ml/L)

                                                                     = 1000ml/10^-3 m^3

                                                                     = 10^6 ml/m^3

                                                                     = 10^6 mg/m^3