In: Statistics and Probability
The average ticket price for a Spring Training baseball game is $30.21, with a standard deviation of $6.15. In a random sample of 40 Spring Training tickets, find the probability that the mean ticket price exceeds $33. (Round your answer to three decimal places)
Solution :
Given that ,
mean = = $30.21
standard deviation = = $6.15
n = 40
= 30.21
= / n =6.15 / 40 = 0.9724
P( >33 ) = 1 - P( 33< )
= 1 - P[( - ) / < (33 -30.21) / 0.9724]
= 1 - P(z <2.87 )
Using z table
= 1 - 0.9979
= 0.0021
probability= 0.002