Question

In: Statistics and Probability

Descriptive analysis revealed that the mean Test 3 score of all 63 students in Dr. Bills’s...

Descriptive analysis revealed that the mean Test 3 score of all 63 students in Dr. Bills’s statistics courses was an 80. Similarly, the standard deviation for all students’ Test 3 scores was found to be 16. Assume the Test 3 scores are approximately normally distributed.

5. Determine the Test 3 score that corresponds to a z-score of -2.18. Round your solution to the nearest whole number.

6. Find the 75th percentile. That is, find the test score such that 75% of all test scores are below it. Hint: See example on the Chapter 6 handout. Round your solution to the nearest whole number.

Solutions

Expert Solution

Mean = = 80

standard deviation = = 16

Sample size = n = 63

5. Determine the Test 3 score that corresponds to a z-score of -2.18. Round your solution to the nearest whole number.

z = -2.18

6. Find the 75th percentile. That is, find the test score such that 75% of all test scores are below it.

We need to find such that

  

We know that


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