Question
In: Statistics and Probability
In a study on the physical activity of people, researchers measured overall physical activity as the...
In a study on the physical activity of people, researchers measured overall physical activity as the total number of registered movements (counts) over a period of time and then computed the number of counts per minute (cpm) for each subject. The study revealed that the overall physical activity of obese people has a mean of μ=322cpm and a standard deviation σ=92cpm. In a random sample of 100 obese people, consider x ̅, the sample mean counts per minute.
Now suppose we are interested in the total activity (Σcpm) of a
random sample of 25 obese people. Answer the following questions on
a separate sheet of paper and upload to "Quiz Ch. 7 Free Response
Answer":
a) Write a distribution statement that describes this new study of
total activity (Σcpm).
b) Find the probability that the total cpm for 25 obese people is
less than 7,500 cpm.
c) Sketch the graph, labeling and scaling the horizontal axis.
Shade the region corresponding to the probability in part b.
d) How likely is it that those 25 people will collectively register
more than 9,000 cpm? Explain how you came to that conclusion.
Solutions
Expert Solution
For
sample of 100 observations the distribution of sample mean is
described with a mean of 322 cpm and the standard deviation of 9.2
cpm. ( standard deviation = 92÷(100)^(+÷2).)
orchestra answered 1 year agoRelated Solutions
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