Find the volume of the figure whose base is the region bounded
by y = x^2 + 4, y = x^2, the y-axis, and the vertical line x =2,
and whose cross sections are squares parallel to the x-axis.
1. The base of a solid is the region in the x-y plane bounded by
the curve y= sq rt cos(x) and the x-axis on [-pi/2, pi/2] . The
cross-sections of the solid perpendicular to the x-axis are
isosceles right triangles with horizontal leg in the x-y plane and
vertical leg above the x-axis. What is the volume of the solid?
2. Let E be the solid generated by revolving the region between
y=x^3 and y= sr rt (x) about...
1.
Find the volume of the region bounded by
y = ln(x), y = 1, y = 2,
x = 0
and rotated about the y-axis. Which method will be
easier for this problem?
2.
Find the volume of the region bounded by
y = 2x + 2, x =
y2-2y
and rotated about y = 2. Which method will be easier
for this problem? NOTE: You do
not need to integrate this problem, just set it up.
Find the volume of the solid obtained by rotating the region
bounded by y = x 3 , y = 1, x = 2 about the line y = −3.
Sketch the region, the solid, and a typical disk or washer
(cross section in xy-plane).
Show all the work and explain thoroughly.
Find the volume of the solid generated by revolving the region
bounded by y = sqrt(x) and the lines and y=2 and x=0 about:
1) the x-axis.
2) the y-axis.
3) the line y=2.
4) the line x=4.