Question

In: Statistics and Probability

A random sample of surgical procedures was selected each month for 30 consecutive months, and the...

A random sample of surgical procedures was selected each month for 30 consecutive months, and the number of procedures with post-operative complications was recorded. The data are listed in the accompanying table.

  1. What type of control chart is the most appropriate to analyze the process?
  2. Compute the critical boundaries for the control chart.
  3. Interpret the chart. Does the process appear to be in control? Explain.

Months

Complications

Procedure Sampled

1

8

107

2

7

90

3

12

70

4

7

103

5

8

70

6

50

100

7

7

65

8

5

80

9

7

97

Solutions

Expert Solution

Answer:-

Given That:-

A random sample of surgical procedures was selected each month for 30 consecutive months, and the number of procedures with post-operative complications was recorded. The data are listed in the accompanying table.

What type of control chart is the most appropriate to analyze the process?

Data is of Yes/No Type is i.e,

# of defectives/cpmplications in a sample. attribute chart is suitable.

Since sample size varies

Therefore p chart is most appropriate.

Compute the critical boundaries for the control chart.

For p-chart (proportion complication)

(for constant sample size)

Since sample sizes are variables.

Therefore Control limits will also be varrying.

is proportion complication for each month

= 111/782

= 0.141944

Therefore For variable Sample size

So From p-chart.

sample # 6 fail & is out of control.

Interpret the chart. Does the process appear to be in control? Explain.

Therefore Process is out of control because sample # 6 has to highest # of complication.

Therefore one need to inspect for the pressure of special cause going to failure of process to remain in control.

Sample sie Complications
107 8
90 7
70 12
103 7
70 8
100 50
65 7
80 5
97 7
Sum 782 111

Below is the minitab output.

Above is the test conducted for special cause. sample # 6 has failed in 1st test so process is out of control.

Plz like it...,


Related Solutions

A random sample of 30 stocks was selected from each of the three major U.S. exchanges...
A random sample of 30 stocks was selected from each of the three major U.S. exchanges and their performance over the previous year was noted. The median performance for all 90 stocks was noted and the following table constructed, Exchange Median New York 18 American 17 NASDAQ 10 Was there a significant difference in the performance of stocks on the three exchanges during the previous year?
Question 1 In the Payne County medical center, a surgical director selected a random sample of...
Question 1 In the Payne County medical center, a surgical director selected a random sample of 37 nurses and found that the mean of their ages was 39.40. The sample standard deviation for the ages is 6.42. The director also selected a random sample of 32 physical therapists and found the mean of their ages was 36.77. The sample standard deviation of ages for the physical therapists is 4.48. A. [3] Give one reason why this data should not be...
A stock price is currently $30. Each month for the next two months it is expected...
A stock price is currently $30. Each month for the next two months it is expected to increase by 8% or reduce by 10%. The risk-free interest rate is 5%. Use a two-step tree to calculate the value of a derivative that pays off [max(30 − ST ; 0)]2, where ST is the stock price in two months? If the derivative is American-style, should it be exercised early?
A simple random sample of 300 colleges and universities was selected and for each it was...
A simple random sample of 300 colleges and universities was selected and for each it was determined whether they planned to move summer 2020 classes online or not. Of the 300 colleges and universities in the sample, 90 responded that they will move summer 2020 classes online , and 210 responded that they will not move summer 2020 classes online. . If appropriate, use this information to calculate and interpret a 99% confidence interval for the proportion of all colleges...
A simple random sample of 30 households was selected from a particular neighborhood. The number of...
A simple random sample of 30 households was selected from a particular neighborhood. The number of cars for each household is shown below. Construct the 98% confidence interval estimate of the population mean. 2 0 1 2 3 2 1 0 1 4 1 3 2 0 1 1 2 3 1 2 1 0 0 5 0 2 2 1 0 2 A) 1.0 cars < μ < 2.0 cars B) 0.9 cars < μ < 2.1 cars C)...
In a large hospital, a nursing director selected a random sample of 30 registered nurses and...
In a large hospital, a nursing director selected a random sample of 30 registered nurses and found that the mean of their ages was 30.2. The population standard deviation for the ages is 5.6. She selected a random sample of 40 nursing assistants and found the mean of their ages was 31.7. The population standard deviation of the ages for the assistants is 4.3. Find the 99% confidence interval of the differences in the ages.
A simple random sample of 5 months of sales data provided the following information: Month: 1...
A simple random sample of 5 months of sales data provided the following information: Month: 1 2 3 4 5 Units Sold: 94 85 85 94 92 (a) Develop a point estimate of the population mean number of units sold per month. x = (b) Develop a point estimate of the population standard deviation. If required, round your answer to two decimal places. s =
A random sample is selected from a normal population with a mean mu equals 30 space...
A random sample is selected from a normal population with a mean mu equals 30 space a n d space s tan d a r d space d e v i a t i o n space sigma equals 8. After a treatment is administered to the individuals in the sample, the sample mean is found to be M=33. (a) If the sample consists of n=16 scores is the sample mean sufficient to conclude that the treatment has a significant...
A stock price is currently $30. During each two-month period for the next four months it...
A stock price is currently $30. During each two-month period for the next four months it will increase by 8% or decrease by 10%. The risk-free interest rate is 4%. Use a two-step tree to calculate the value of a derivative that pays off [max(30-ST, 0)]2, where ST is the stock price in four months. If the derivative is American-style, should it be exercised early?
Assume a normal population with known variance σ2, a random sample (n< 30) is selected. Let...
Assume a normal population with known variance σ2, a random sample (n< 30) is selected. Let x¯,s represent the sample mean and sample deviation. (1)(2pts) write down the formula: 98% one-sided confidence interval with upper bound for the population mean. (2)(6pts) show how to derive the confidence interval formula in (1).
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT