Question

write the following C program that ccepts command-line arguments following argv[0] — up to 20 decimal integer literals.

Each of these decimal integer literals will be expressed using decimal digits, only, and none of the decimal integer literals will be prefixed by a plus or minus sign.

None of the decimal integer literals will be greater than ULONG_MAX.

The program prints the integers in order, least-to-greates and also prints the sum of the integers.

Answer 1

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Program

#include<stdio.h>
#include <stdlib.h>
// Taking argument as command line
int main(int argc, char *argv[])
{
    int total = 0,arr[20];
    int i,j=0,n=20,temp;
    //Read command line arguments into an array
    for(i = 1; i < argc; i++)
    {
        arr[j]=atoi(argv[i]);
        total+=arr[j];
        j++;
    }
    printf("Numbers before sorting : \n");
    for(i=0;i<n;i++)
    printf(" %d\t", arr[i]);
  
    //Sorting the numbers
   for (i = 0; i < n-1; i++)     
    {
       for (j = 0; j < n-i-1; j++)
       {
           if (arr[j] > arr[j+1])
              {
                int temp = arr[j];
                arr[j]= arr[j+1];
                arr[j+1] = temp;
              }
       }
    }
     
    printf("\nNumbers after sorting : \n");
    for(i=0;i<n;i++)
    printf(" %d\t", arr[i]);

    printf("\nSum= %d\n", total);

  
   return 0;
}

Command line arguments

1       2       3       5       8       56      78      12      98      534      9        23      986     1       7       54      90      45      42      3   

Output

Numbers before sorting :
1   2   3   5   8   56   78   12   98   534   9   23   986   1   7   54   90   45   42   3  
Numbers after sorting :
1   1   2   3   3   5   7   8   9   12   23   42   45   54   56   78   90   98   534   986  
Sum= 2057