In: Statistics and Probability
Let's say ophthalmologist measures the average visual acuity for both samples. Then we need to test that there is difference in the average both of both the sample i.e they are not same.
Null hypothesis would be Ho: average visual acuity is same for both groups.
Alternative :
t test for the difference of means would be used as samples are small.
decision rule is mentioned above in the image in the last two lines.
if t calculated < t tabulated @ significance level 0.05 for n1+n2-2 degrees of freedom we accept otherwise we reject.
C) for this part as both eyes are of the same person so they are dependent.
and as sample is small and normal we used paired -t test for difference of means
calculate d=x-y
for all observations and then calculate
use this t-statistic for testing.
null hypothesis Ho; there is no significant difference between visual acuity of right and left eye.
alternative; (r-right and l-left)
you can take same 0.05 significance.
b) This part is slightly confusing . the best I can say for this is that we can use Mann -Whitney wilcoxon U -test (Non parametric) doesn't need any distribution assumptions.
right now I have this much information for this part ... i will be updating my answer soon for this part.
Thanks