a) Calculate the entropy change of the UNIVERSE when 1.732 moles of CO2(g) react under standard...

a) Calculate the entropy change of the UNIVERSE when 1.732 moles of CO2(g) react under standard conditions at 298.15 K.

6CO₂(g) + 6H₂O(l)C₆H₁₂O₆ + 6O₂(g)

for which H° = 2.801×10³ kJ and S° = -259.0 J/K at 298.15 K.

b) Is this reaction reactant or product favored under standard conditions?

c) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored, choose 'reactant favored'.

Solutions

Expert Solution

a) Change of entropy of the universe:

Now,

b) The reaction is reactant favoured as entropy decreased after reaction and also the change of free energy is positive in the forward reaction.

queen_honey_blossom answered 1 year ago

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