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Question 3, and 4 2.(50 pts) For the following list of nuclides, complete the following: List...

Question 3, and 4

2.(50 pts) For the following list of nuclides, complete the following:

List the number of protons

Hydrogen-1= 1

Iron-56 =26

Zirconium-91= 40

Gold-197 =79

Uranium-238: 92

List the number of neutrons

Hydrogen-1 = 0

Iron-56 = 30

Zirconium-91 = 51

Gold-197 = 118

Uranium-238: 146

Write out the nuclide in the form  

Hydrogen-1 = 1 H 1

Iron-56 = 56 Fe 26

Zirconium-91 = 91 Zr 40

Gold-197 = 197 Au 79

Uranium-238 = 238 U 92

Calculate the mass defect of each nuclide and associated binding energy

Hydrogen-1 (mass defect = .007316 amu ) (Total mass = 1.007316)

Iron-56 : (Mass Defect = 0.450166 amu) (Total Mass = 56.450166)

Zirconium-91 (Mass defect = 0.734555 amu) (total mass = 91 amu)

Gold-197(Mass defect = 1.600434 amu) (Total mass = 198.600434)

Uranium-238: (Mass defect= -1.934205) Total mass = 92 x 1.007316 + 146 x 1.008665 = 239.9 0r 238

3. (10 pts) For the isotopes in the previous problem, indicate if they are naturally occurring and/or radioactive. If radioactive, provide the half-life. If naturally occurring, provide the isotopic percentage.

4. (10 pts) For the isotopes in problem 2, calculate the binding energy per nucleon and plot this value versus the mass number.

Solutions

Expert Solution

3.Ans). H1 is naturally occurring isotope. Isotopic percentage = 99.98 %

Fe56  is naturally occurring isotope. Isotopic percentage = 91.754 %

Zr91 is naturally occurring isotope. Isotopic percentage = 11.22 %

Au197 is naturally occurring isotope. Isotopic percentage = 100 %

U238 is a radioactive isotope. Half life = 4.468 billon years

4.Ans).  Binding Energy = binding energy is the energy required to split a nucleus of an atom into its components.The value of binding energy per nucleon gives a measure of the stability of that nucleus. Greater is the binding energy per nucleon of a nucleus, more stable is the nucleus. It is calculated as :

Binding Energy = ( Mass Defect x 931.5 MeV ) / no. of nucleons

According to the mass defects values provided in question, following results are obtained for Binding Energies :

Elements    Binding Energy (MeV) Mass Number
H1 (0.007316 x 931.5) / 1 = 6.815 1
Fe56 (0.450166 x 931.5) / 56 = 7.488 56
Zr91 (0.734555 x 931.5) / 91 = 7.519 91
Au197 (1.600434 x 931.5) / 197 = 7.568 197
U238 (1.934205 x 931.5) / 238 = 7.570 238

Binding energy per nucleon versus the mass number plot :

Thanks


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