A 80.0 g silver object and a 80.0 gold are both added to 64.4 mL of...

A 80.0 g silver object and a 80.0 gold are both added to 64.4 mL of water contained in a graduated cylinder. what is the new water level, in millimeters, in the cylinder

Expert Solution

queen_honey_blossom answered 2 years ago

Suppose silver (S) and gold (G) are substitutes for each other because both serve as hedges...

Suppose silver (S) and gold (G) are substitutes for each other because both serve as hedges against inflation. Suppose also that the supplies of both are fixed in the short run (QS= 250 and QG=150) and that the demands for silver and gold are given by the following equations: PS=600-QS+0.5PG PG=1050-QG+0.5PS What are the equilibrium prices of the silver and gold? What if a new discovery of gold doubles the quantity supplied to 300. How will this discovery affect the...

70.0 mL base with 2.00 M molarity is added to 80.0 mL Oxalic acid with 1.80...

70.0 mL base with 2.00 M molarity is added to 80.0 mL Oxalic acid with 1.80 M molarity. The initial temperature is 20.0 °C and specific heat capacity is assumed to be the same as water (4.184 J/ g °C). Once the reaction reached thermal equilibrium, the temperature became 32.72°C. Find the enthalpy of neutralization for base.

1) Thirty grams of silicon at 80.0°C is added to 70.0 mL of water at 20.0°C....

1) Thirty grams of silicon at 80.0°C is added to 70.0 mL of water at 20.0°C. Calculate the final temperature after the two substances are mixed together. The specific heat of water is 4.184 J/g°C and the specific heat of silicon is 0.7121 J/g°C. 2) A cube of brass, 2 cm on a side, is heated until the temperature of the brass is 75oC. The cube is quickly added to 100 mL of water at 23oC. What is the final...

A 37.5 g piece of gold at 83.0 �C is added to 100.0 g H2O at...

A 37.5 g piece of gold at 83.0 �C is added to 100.0 g H2O at 22.0 �C in a well-insulated cup. What is the temperature after the system comes to equilibrium? (The specific heat capacity of Au is 0.129 J�g�1�K�1)

Silver sulfate solution is added to 25.00 mL of a 0.500 M potassium chloride solution until...

Silver sulfate solution is added to 25.00 mL of a 0.500 M potassium chloride solution until no more precipitate forms. What mass of silver chloride will be formed? What concentration of potassium will remain in solution after the reaction is complete if 45 mL of silver sulfate solution were added to the potassium chloride solution?

Fast $, Inc produces silver and gold pendants. The data are as follows: Silver

Fast $, Inc produces silver and gold pendants. The data are as follows: Silver Gold Price $30 $125 Material 8 35 Labor 5 73 Contribution Margin Labor Hours Required $0 .75 $1.00 Demand 100 75 Fixed Costs = $10,000; Labor hours available = 100 Are there enough labor hours to satisfy demand for both types?_____ Determine the contribution margin per labor hours for each How many silver pendants and how many gold pendants would maximize profits?...

Suppose that 0.86 g of water condenses on a 80.0 −g block of iron that is...

Suppose that 0.86 g of water condenses on a 80.0 −g block of iron that is initially at 22 ∘C. If the heat released during condensation goes only to warming the iron block, what is the final temperature (in ∘C) of the iron block? (Assume a constant enthalpy of vaporization for water of 44.0 kJ/mol.) Answer in Torr.

A consumer has 10 pounds of gold and 20 pounds of silver. The price of gold...

A consumer has 10 pounds of gold and 20 pounds of silver. The price of gold ?) = $4,000 a pound while the price of silver ?* = $1,000 a pound. Gold and silver are the only two goods that can be consumed. Write down the budget constraint of this consumer and draw it on a graph. Suppose that the price of silver increases to $2,000 a pound. Draw the new budget constraint. Has the purchasing power of our consumer...

A sample of 9.20 g of solid calcium hydroxide is added to 37.5 mL of 0.440...

A sample of 9.20 g of solid calcium hydroxide is added to 37.5 mL of 0.440 M aqueous hydrochloric acid. Enter the balanced chemical equation for the reaction. Physical states are optional and not graded. What is the limiting reactant? How many grams of salt are formed after the reaction is complete? How many grams of the excess reactant remain after the reaction is complete?

A sample of 3.53 g of K3PO4 is added to 75.3 mL of 0. 545 M...

A sample of 3.53 g of K3PO4 is added to 75.3 mL of 0. 545 M AgNO3, resulting in the formation of 4.86 g of a Ag3PO4 precipitate. Calculate the percentage yield of the reaction. 3Ag+(aq) + PO4 (aq) → Ag3PO4(s)

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