Question

For the reaction shown, compute the theoretical yield of the product (in grams) for each of the following initial amounts of reactants.
Ti(s)+2F2(g)→TiF4(s)

1)7.0 g Ti , 7.0 g F2

Express your answer using two significant figures.

m= ______ g

2) 2.3 g Ti , 1.5 g F2

Express your answer using two significant figures.

m=_______ g

3) 0.236 g Ti , 0.292 g F2

M =_____ g

Answer 1

(1)

Ti(s)         +    2F2(g) ----------------------> TiF4(s)

47.87g             76                                       123.87

7                      7

here limiting reagent : F2

76 g F2 gives --------------------> 123.87 g TiF4

7 g F2 gives ------------------------> x g TiF4

x = 7 x 123.87 / 76

theoretical yield of the product = 11.4 g

(2)

Ti(s)         +    2F2(g) ----------------------> TiF4(s)

47.87g             76                                       123.87

2.3                   1.5

here limiting reagent : F2

76 g F2 gives --------------------> 123.87 g TiF4

1.5 g F2 gives ------------------------> x g TiF4

x = 1.5 x 123.87 / 76

theoretical yield of the product = 2.44 g

(3)

Ti(s)         +    2F2(g) ----------------------> TiF4(s)

47.87g             76                                       123.87

0.236             0.292

here limiting reagent : F2

76 g F2 gives --------------------> 123.87 g TiF4

0.292 g F2 gives ------------------------> x g TiF4

x = 0.292 x 123.87 / 76

theoretical yield of the product = 0.476 g