In: Statistics and Probability
a) Number of different codes that are possible here given that repetition is permitted is computed here as:
= 262 * 105
= 67600000
Therefore 67600000 codes are possible here.
b) Given that repeition is not allowed, but first 2 letters should be same, the number of codes here is computed as:
= Number of ways to choose one of the 26 letters * Number of permutation of 10 digits taken 5 at a time
= 26*10*9*8*7*6
= 786240
Therefore 786240 codes are possible here.
c) Number of codes possible here is computed as:
= Number of ways to choose the first letter * Number of ways to choose second letter from remaining 25 letters * Number of permutation of 10 digits taken 5 at a time
= 5*25*(10! / 5!)
= 3780000
Therefore 3780000 codes are possible here.