Question

In: Statistics and Probability

Create the printout for testing whether the mean low stock price of all NYSE stocks differs...

  1. Create the printout for testing whether the mean low stock price of all NYSE stocks differs from $35 and attach it here. Answer the following questions regarding this printout:

Student Edition of Statistix 10.0                          4/21/2020, 5:29:39 AM

One-Sample T Test

Null Hypothesis: μ = 35

Alternative Hyp: μ ≠ 35

                                                                               Lower    Upper

Variable Mean       SE         T       DF             P      95% C.I. 95% C.I.

Low      28.369   5.2626   -1.26     64         0.2123   17.856 38.883

Cases Included 65    Missing Cases 0

  1. In the words of the problem, give a practical conclusion for this test. Make sure to include your choice of α in this conclusion.
  2. In the words of the problem, state what a Type I error would be.
  3. Use your knowledge of p-values and the printout above to state what the p-value would have been if you were conducting a one-tailed test instead of the two-tailed test I asked for.

Solutions

Expert Solution

We Have,

One-Sample T Test

Null Hypothesis: μ = 35

Alternative Hyp: μ ≠ 35

                                                                               Lower    Upper

Variable Mean       SE         T       DF             P      95% C.I. 95% C.I.

Low      28.369   5.2626   -1.26     64         0.2123   17.856 38.883

Cases Included 65    Missing Cases 0

Answer(a): From given output of one sample t-test, we can see that p-value is 0.2123 which suggest that we fail to reject the null hypothesis and we can conclude that mean low stock price of all NYSE stocks does not differs from $35 at 0.05 level of significance.

Answer(b): Type-I error is defined as rejecting a true null hypothesis. In this Problem if we conclude that the mean low stock price of all NYSE stocks differs from $35 then we will commit a type I error.

Answer(c): The p-value for a one-tailed test is just half of the p-value for a two-tailed test.

So for this problem the p-value would have been 0.10615 if we were conducting a one-tailed test.


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