In: Statistics and Probability
Consider the following linear programming problem:
Maximize Profit 30X + 50Y
Subject to 4X + 5Y = 40,000
X ≥ 3,000
Y ≥ 4,000
X ≥ 0 and Y ≥ 0
here using given LPP we find optimal solution by ghraphical method for simplicity we take X= x1 and Y= x1 and find the solution
Here we gate the value of X = x1 = 3000 and Y = x2 = 5600
then put this value in the objective function Maximize Profit = 30X + 50Y
Therefore maximum profit = (30 * 3000) + (50 * 5600)
Hence Mxa Z = Maximum profit = 370000
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