In: Statistics and Probability
A | C | D | |
11 | 211 | 211 | |
12 | 125 | 121 | |
7 | 179 | 185 | |
12 | 225 | 222 | |
11 | 161 | 157 | |
15 | 170 | 174 | |
6 | 191 | 184 | |
16 | 195 | 194 | |
12 | 135 | 133 | |
13 | 162 | 165 | |
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Use the central limit theorem to the following questions.
We want to test to see whether the data taken from 25 test experiments is consistent with the mean equal to 10.3 (µ = 10.3), or is more consistent with the mean greater than 10.3 (µ > 10.3).
Use Summary 5b, Table 2, Column 1.
You are measuring weight loss using the same set of people at different times C and D. You want to know whether there is any difference in the weight between the start of the diet and the end of the diet. Column C gives the weight at the beginning of diet time. Column D gives the weight for the SAME person at the end of the diet time. Since there is data for the same person at different times, we will test whether µ(C-D) <= 0 or µ(C-D) > 0 (meaning the diet did cause weight loss) since we have correlated data (matched pairs).
Use Summary 5b, Table 2, Column 1
a)
µ= 80
σ = 4
proportion= 0.7
Z value at 0.7 =
0.52 (excel formula =NORMSINV(
0.7 ) )
z=(x-µ)/σ
so, X=zσ+µ= 0.52 *
4 + 80
X =
82.10
b)
Z=(X-µ)/σ= (75-80)/4)= -1.25
c)
µ = 80
σ = 4
we need to calculate probability for ,
P ( 85 < X <
100 )
=P( (85-80)/4 < (X-µ)/σ < (100-80)/4 )
P ( 1.250 < Z <
5.000 )
= P ( Z < 5.000 ) - P ( Z
< 1.250 ) =
1.0000 - 0.8944 =
0.1056
Use the central limit theorem to the following questions.
a)
S.D. = σ/ sqrt(n)
= 4/ sqrt(9)
= 4/3 = 1.33
b)
µ = 80
σ = 4
n= 9
we need to calculate probability for ,
90 ≤ X ≤ 100
X1 = 90 , X2 =
100
Z1 = (X1 - µ )/(σ/√n) = ( 90
- 80 ) / ( 4 /
√ 9 ) = 7.50
Z2 = (X2 - µ )/(σ/√n) = ( 100
- 80 ) / ( 4 /
√ 9 ) = 15.00
P ( 90 < X <
100 ) = P ( 7.5
< Z < 15.0 )
= P ( Z < 15.00 ) - P ( Z
< 7.50 ) =
1.00000 - 1.00000 =
0.00000000000003186
Please revert in case of any doubt.
Please upvote. Thanks in advance