In: Statistics and Probability
In her first year of university, Mary recieved the following
grades: 12, 7, 11, 11, 12, 11 Similarly in his first year, Bob recieved the following grades: 11, 11, 9, 11, 9, 8 |
(a) | Compute the population mean and variance for Mary's grades. |
(b) | Compute the population mean and variance for Bob's grades. |
Solution(a)
Given in the question
Mary received the following grades in her first year of
university
12,7,11,11,12,11
So population mean can be calculated as
Population mean (mary)
=
Xi/n = (12+7+11+11+12+11)/6= 64/6 = 10.67
Population variance can be calculated as
Population variance(^2)
=
(Xi-mary)^2
/n = ((12-10.67)^2 + (7-10.67)^2 + (11-10.67)^2 + (11-10.67)^2 +
(12-10.67)^2 + (11-10.67)^2)/6 = 17.33/6 = 2.89
Solution(b)
Given in the question
Bob received the following grades in her first year of
university
11,11,9,11,9,8
So population mean can be calculated as
Population mean (Bob)
=
Xi/n = (11+11+9+11+9+8)/6= 58/6 = 9.83
Population variance can be calculated as
Population variance(^2)
=
(Xi-Bob)^2
/n = ((11-9.83)^2 + (11-9.83)^2 + (9-9.83)^2 + (11-9.83)^2 +
(9-9.83)^2 + (8-9.83)^2)/6 = 8.83/6 = 1.47