In: Statistics and Probability
For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
In a random sample of 530 judges, it was found that 279 were
introverts.
(b) Find a 99% confidence interval for p. (Round your answers to two decimal places.)
lower limit | |
upper limit |
Solution :
Given that,
n = 530
x = 279
Point estimate = sample proportion = = x / n = 279/530=0.5264
1 - = 1- 0.5264=0.4736
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z / 2 * (((( * (1 - )) / n)
= 2.576* (((0.5264*0.4736) /530 )
E = 0.0559=0.06
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.5264-0.06 < p < 0.5264+0.06
0.47< p < 0.59