For the data set below, find the upper outlier boundary. 154 160 146 131 148 164...

For the data set below, find the upper outlier boundary.
154 160 146 131 148 164 199 169 139 165

		199
		19
		165
		193.5

Expert Solution

For the given data we first find the first and third quartiles using Excel function Qurtile.Exc
Q1 = Quartile.exc(data, 1)
Q1 = 144.25

Q3 = Quartile.exc(data, 3)
Q3 = 166

Inter Quartile Range
IQR = Q3 - Q1
        = 166 - 144.25
        = 21.75
Upper outlier boundary is given by
Q3 + 1.5 * IQR
= 166 + 1.5 * 21.75
= 198.625

Upper outlier boundary is = 198.625

Hence, the observation 199 is an outlier as it is greater than 198.625

orchestra answered 1 year ago

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