In: Statistics and Probability
Here' the answer to the question. please write back in case you've doubts.
Normal distribution parameters are :
Mean = 119
Stdev = 25
standardizing formula: Z = (X-Mean)/Stdev
a.
P(has stage 2 high blood pressure)
= P(X>160)
= P(Z> (160-119)/25)
= P(Z>1.64)
= 0.0505
b. P(has stage 1 high blood pressure)
= P(140<X<160)
Standardizing,
= P( (140-119)/25 < Z < (160-119)/25)
= P(0.84<Z<1.64)
= 0.94950- 0.8000
= 0.1500
c. The Z for a cumulative of 30 percnetage is -0.5244
The score will be lets "c" such that
P(X<c) = .3
(c-119)/25 = -0.5244
c = 105.8900 mmHg
So, if doctor says you are in 30th percentile for bp amoung US adults you have a systolic BP of 105.8900 mmHg
d.
To be in the top 2.5% of bp you should have a standardized score
of at least +1.96
Let such a score be c
So, P(X>c) = .025
or P(X<=c) = 1-.025 = .975
(c-119)/25 = +1.96
c = 168
So, you must have a 168 mmHg systolic BP to be in top 2.5% of the US adults