Question

In: Statistics and Probability

(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 229 of...

(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 229 of 416 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places.

1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th

2. Calculate the standard error for the point estimate you calculated in part 1.

3. Calculate the margin of error for a 99 % confidence interval for the proportion of Kansas residents that planned to set off fireworks on July 4th.

4. What are the lower and upper limits for the 99 % confidence interval.

( ,  )

5. Use the information from Survey USA poll to determine the sample size needed to construct a 90% confidence interval with a margin of error of no more than 4.2%. For consistency, use the reported sample proportion for the planning value of p* (rounded to 4 decimal places) and round your Z-value to 3 decimal places. Your answer should be an integer.

Solutions

Expert Solution

Answer:

Given that,

n = 416

x = 229

1) Point estimate = sample proportion = = x / n = 229 / 416 = 0.5504

1 - = 1 - 0.5504 = 0.4496

2) =  [p( 1 - p ) / n] = [(0.5504 * 0.4496) / 416 ]

= 0.0243

3)

At 90% confidence level

= 1 - 99%

=1 - 0.99 =0.01

/2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z / 2 *

= 2.576 * 0.0243

= 0.0625

4) A 99% confidence interval for population proportion p is ,

± E  

= 0.5504 ± 0.0625

= ( 0.4879 , 0.6129 )

5) margin of error = E = 0.042

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.645/ 0.042)2 * 0.5504 * 0.4496

= 379.61

sample size = n = 380

NOTE:: I HOPE THIS ANSWER IS HELPFULL TO YOU......**PLEASE SUPPORT ME WITH YOUR RATING......

**PLEASE GIVE ME "LIKE".....ITS VERY IMPORTANT  FOR,ME......PLEASE SUPPORT ME .......THANK YOU


Related Solutions

(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 364 of...
(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 364 of 617 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places. 1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th 2. Calculate the standard error for the point estimate you calculated in part 1. 3. Calculate the margin of error for a 90 %...
(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 254 of...
(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 254 of 438 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places. 1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th 2. Calculate the standard error for the point estimate you calculated in part 1. 3. Calculate the margin of error for a 90 %...
(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 301 of...
(1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 301 of 538 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places. 1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th 2. Calculate the standard error for the point estimate you calculated in part 1. 3. Calculate the margin of error for a 99 %...
6.3 (1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 337...
6.3 (1 point) Fireworks. Last summer, Survey USA published results of a survey stating that 337 of 571 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places. 1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th 2. Calculate the standard error for the point estimate you calculated in part 1. 3. Calculate the margin of error for a 90...
Fireworks. Last summer, Survey USA published results of a survey stating that 342 of 645 randomly...
Fireworks. Last summer, Survey USA published results of a survey stating that 342 of 645 randomly sampled Kansas residents planned to set off fireworks on July 4th. Round all results to 4 decimal places. 1. Calculate the point estimate for the proportion of Kansas residents that planned to set off fireworks on July 4th 2. Calculate the standard error for the point estimate you calculated in part 1. 3. Calculate the margin of error for a 99 % confidence interval...
5. Fireworks on July 4th. In late June 2012, Survey USA published results of a survey...
5. Fireworks on July 4th. In late June 2012, Survey USA published results of a survey stating that 56% of the 600 randomly sampled Kansas residents planned to set of fireworks on July 4th. Determine the margin of error for the 56%-point estimate using a 95% confidence level. What is the 95% confidence Interval? Find 99% confidence Interval? Which of these intervals is wider? Why?
In the summer of 2003, The New England Journal of Medicine published results of some Scandinavian...
In the summer of 2003, The New England Journal of Medicine published results of some Scandinavian research. Men diagnosed with prostate cancer were randomly assigned to either undergo surgery or not. Among the 347 men who had surgery (group 1), 16 eventually died of prostate cancer compared with 31 of the 348 men (group 2) who did not have surgery. The researchers want to determine if surgery increases the chance of survival. Let p1: proportion of men that survived after...
When the results of a survey or poll are published, the sample size and the margin...
When the results of a survey or poll are published, the sample size and the margin of error are both given. For example: 1000 voters were surveyed and 39±2% of the voters agree with the president. In this example N=1000 and the margin of error (MoE) is 2%. This website lists several public opinion polls. Search the site and find a poll where the sample size and margin of error are given. Try to find a poll dealing with a...
When the results of a survey or a poll are published, the sample size is usually...
When the results of a survey or a poll are published, the sample size is usually given, as well as the margin of error. For example, suppose the Honolulu Star Bulletin reported that it surveyed 385 Honolulu residents and 78% said they favor mandatory jail sentences for people convicted of driving under the influence of drugs or alcohol (with margin of error of 3 percentage points in either direction). Usually the confidence level of the interval is not given, but...
(1 point) Given the results of the in-class visible minority survey, an employment equity survey is...
(1 point) Given the results of the in-class visible minority survey, an employment equity survey is likely to _______________ over-estimate, correctly estimate, under-estimate the percent of a workforce that is composed of persons from visible minorities. (1 point) A job can be identified as belonging to a male job class if ___________ percent of the employment are men. (1 point) The Indian system of dowry ________________ ( is / is not) based on religion, and _____________ (does / does not)...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT