Question

In: Statistics and Probability

An article in Electronic Packaging and Production (2002, vol. 42) considered the effect of X-ray inspection...

An article in Electronic Packaging and Production (2002, vol. 42) considered the effect of X-ray inspection of integrated circuits. The radiation dose (rads) were studied as a function of current (in milliamps) and exposure (in minutes).The data are in excel file uploaded to Moodle. Name of the file is “Assignment 4 Data”. Use a software (preferable MINITAB) to answer the following questions

Part 2. Now, add current to the model and perform multiple regression analysis. (Include the output in your pdf file.)

a) Write the fitted model.

b) Is the model overall significant? Test at significance level of 5%.

c) Is current a significant variable for the model? Test at α=0.05.

d) Use the model to estimate mean radiation dose when the current is 25 mA and exposure time is 30 seconds.

e) Do you observe an improvement in coefficient of determination? Explain

***Assume that you have data of radiation dose, exposure time and mA for 40 samples. Can you solve the problem above using minitab amd show the steps please?

Rads mA Exposure Time
7,4 10 0,25
14,8 10 0,5
29,6 10 1
59,2 10 2
88,8 10 3
296 10 10
444 10 15
592 10 20
11,1 15 0,25
22,2 15 0,5
44,4 15 1
88,8 15 2
133,2 15 3
444 15 10
666 15 15
888 15 20
14,8 20 0,25
29,6 20 0,5
59,2 20 1
118,4 20 2
177,6 20 3
592 20 10
888 20 15
1184 20 20
22,2 30 0,25
44,4 30 0,5
88,8 30 1
177,6 30 2
266,4 30 3
888 30 10
1332 30 15
1776 30 20
29,6 40 0,25
59,2 40 0,5
118,4 40 1
236,8 40 2
355,2 40 3
1184 40 10
1776 40 15
2368 40 20

Solutions

Expert Solution

Stat -> regression -> regression

a)
rads^ = -440.4 + 19.15 mA + 68.08 Exposure time

b)
F = 99.67, p-value = 0.0000 < alpha
hence the model is significant

c)
yes, p-value of mA = 0.000 < alpha

d)
rads^ = -440.4 + 19.15 *25 + 68.08*30
= 2080.75

e) R^2 = 79.57 % {compare with previous model)


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