In: Statistics and Probability
Using the data below, test the null hypothesis that the variance in the Close Ratio for the sample of employees is at most 1.5% at 5% significance level.
Years Employed | Gender | Certified | Prior Background | Close Ratio | Sales |
7 | M | Y | Y | 44.40% | $ 201,500 |
8 | M | Y | Y | 54.20% | $ 129,000 |
4 | M | Y | Y | 60.70% | $ 101,100 |
8 | M | N | N | 42.60% | $ 99,700 |
6 | M | Y | N | 68.30% | $ 98,100 |
6 | M | N | N | 37.90% | $ 93,900 |
2 | M | N | N | 29.50% | $ 90,800 |
2 | M | N | N | 42.40% | $ 90,600 |
7 | M | Y | Y | 37.70% | $ 89,200 |
2 | M | N | N | 35.00% | $ 86,600 |
2 | M | N | N | 45.80% | $ 83,900 |
3 | M | N | N | 50.70% | $ 80,000 |
4 | M | Y | Y | 29.80% | $ 77,300 |
7 | M | N | N | 38.70% | $ 67,100 |
5 | M | Y | Y | 62.20% | $ 58,900 |
3 | M | Y | Y | 63.20% | $ 56,600 |
6 | M | N | N | 18.60% | $ 54,700 |
3 | F | Y | Y | 32.00% | $ 126,300 |
4 | F | Y | Y | 50.00% | $ 95,800 |
9 | F | Y | Y | 51.70% | $ 93,100 |
2 | F | N | Y | 29.20% | $ 91,600 |
2 | F | N | N | 58.20% | $ 89,000 |
4 | F | Y | Y | 44.00% | $ 82,300 |
8 | F | Y | Y | 67.70% | $ 81,000 |
6 | F | N | Y | 61.20% | $ 78,200 |
7 | F | N | Y | 54.40% | $ 71,300 |
8 | F | N | Y | 38.60% | $ 67,500 |
2 | F | Y | Y | 40.40% | $ 64,800 |
4 | F | N | Y | 41.50% | $ 57,200 |
2 | F | N | Y | 40.70% | $ 54,100 |
2 | F | N | Y | 36.30% | $ 51,700 |
Variance=1.5 implies SD=1.224744871
Here we are to test
Here the sample size n=31
Let the sample mean be and the parent population from which the sample is drawn follows Normal distribution.
The test statistic is given by
and under
Now for the calculation of the statistic, the following table is made:
Close Ratio ( in %) | |
44.4 | 3.524703 |
54.2 | 62.76728 |
60.7 | 208.0108 |
42.6 | 13.52341 |
68.3 | 484.9941 |
37.9 | 70.18115 |
29.5 | 281.4818 |
42.4 | 15.03438 |
37.7 | 73.57212 |
35 | 127.1802 |
45.8 | 0.227929 |
50.7 | 19.55922 |
29.8 | 271.5053 |
38.7 | 57.41728 |
62.2 | 253.5286 |
63.2 | 286.3737 |
18.6 | 766.0395 |
32 | 203.8447 |
50 | 13.85761 |
51.7 | 29.40438 |
29.2 | 291.6383 |
58.2 | 142.1479 |
44 | 5.186639 |
67.7 | 458.927 |
61.2 | 222.6834 |
54.4 | 65.97632 |
38.6 | 58.94277 |
40.4 | 34.54406 |
41.5 | 22.82374 |
40.7 | 31.10761 |
63.3 | 289.7683 |
Total | 4865.774 |
Hence the test statistic is obtained as
The critical value, as obtained from the Biometrika table, is
As the observed value is greater than that the critical value, we reject the null hypothesis at 5% level of significance and hence conclude that the variance of the close ratio is more than 1.5% at 5% level of significance.
Hopefully this will help you. In case of any query, do comment. If you are satisfied with the answer, give it a like. Thanks.