Question
In: Statistics and Probability
Using the data below and the 5 steps of null hypothesis testing for a chi-square goodness...
- Using the data below and the 5 steps of null hypothesis testing for a chi-square goodness of fit test examine if the frequency of confirmed COVID-19 cases are equally proportionate between the states of Wyoming, North Dakota, Nebraska, and South Dakota (p < .05).
**Data retrieved from Center for Disease Control (April 22, 2020)**
|
Observed Frequencies |
|
|
Wyoming |
430 |
|
N. Dakota |
627 |
|
Nebraska |
1648 |
|
S. Dakota |
1675 |
Solutions
Expert Solution
Null hypothesis : The 4 states have equal proportion of cases
Alternate hypothesis: At least one state have different proportion
alpha = 0.05
| Event | Observed Frequency(O) | Expected Probability | Expected Frequency ( E) | ( O-E)^2 | ( O-E)^2/E |
| Wyoming | 430 | 0.25 | 1095 | 442225 | 403.8584475 |
| N. Dakota | 627 | 0.25 | 1095 | 219024 | 200.0219178 |
| Nebraska | 1648 | 0.25 | 1095 | 305809 | 279.2776256 |
| S. Dakota | 1675 | 0.25 | 1095 | 336400 | 307.2146119 |
| Total | 4380 | 1 | 4380 | 1303458 | 1190.372603 |
The chi square statistic = 1190.372
The corresponding p value is 0.00000
Since p < alpha ( 0.05 )
We reject the null hypothesis
or, At least one state have different proportion
orchestra answered 3 years agoRelated Solutions
Using the data below and the 5 steps of null hypothesis testing for a one-way between-groups...
Using the data below and the 5 steps of null hypothesis testing
for a one-way between-groups ANOVA, examine if adults from
Ohio, Michigan, and New York differ in the average number of years
of education completed (p < .05).
Ohio
X
Michigan
X
New York
X
15
13
10
15
12
17
12
14
15
You will be doing Chi-square goodness-of-fit testing on the M&M’s in a bag. Steps: 1. Count...
You will be doing Chi-square goodness-of-fit testing on the
M&M’s in a bag. Steps: 1. Count the number of M&M’s in your
bag by color. Red: 12 brown 8 Orange 13 yellow 15 green 9 blue 11
2. Now follow the steps for Hypothesis testing: i. State Null and
Alternate hypothesis. Your hypothesis must be based on the
assumption that the M&M’s in your bag are expected to follow
the following pattern: 24% cyan blue, 20% orange, 16% green, 14%...
Use the chi-square test for goodness of fit to determine if the data shown below are...
Use the chi-square test for goodness of fit to determine if the
data shown below are consistent with an inheritance pattern of
simple dominance. Use p = 0.05 for determining
significance.
Cross: Aa x Aa
Offspring:
70 dominant phenotype
30 recessive phenotype
A. The data are consistent with a simple dominance pattern of
inheritance.
B. The data are not consistent with a simple dominance pattern
of inheritance.
State what is the null hypothesis in a chi-square test & what is the alternative hypothesis...
State what is the null hypothesis in a chi-square test
& what is the alternative hypothesis
Explain what probability is represented by the p-value.
What can you conclude when p-value is below
the threshold of significance (e.g., p = 0.05)?
What would you conclude when p-value is above
the critical value?
Is there a statistically significant association between one of
the alleles tested and the Taster phenotype?
Which genotype is over-represented in the Non-Tasters?
Which allele is over-represented in the...
3) Write your null hypothesis, perform a chi-square analysis, and answer the questions. a. Null Hypothesis:...
3) Write your null hypothesis, perform a chi-square analysis,
and answer the questions.
a. Null Hypothesis:
Data
Observed
Expected
O - E
(O – E)2
(O – E)2/E
Round Yellow
910
Round Green
290
Wrinkled Yellow
320
Wrinkled Green
80
b. Degrees of freedom =
c. X2 =
d. p =
e. Fail to Reject or Reject null hypothesis?
Using chi-square, test the null hypothesis that the prevalence of serious mental illness does not differ...
Using chi-square, test the null hypothesis that the prevalence
of serious mental illness does not differ by type of substance
abuse.
A sample of 118 college students is asked whether they are
involved in campus activities. Using the following cross tabulation
depicting student responses by the region in which their colleges
are located, conduct a chi-square test of significance for regional
differences.
Campus Activity Participation
Region
Involved Uninvolved
East
19
10
South
25
6
Midwest
15
15
West
8
20
Choose either the Chi Square Goodness of Fit test OR the Chi Square Test for Independence....
Choose either the Chi Square Goodness of Fit test OR the Chi
Square Test for Independence. Give an example of a research
scenario that would use this test, including your hypothesis AND
what makes the test suitable for your variables chosen
Using the Sample Hypothesis Test Data and Chi-Square Data with a .05 level of significance, provide...
Using the Sample Hypothesis Test Data and Chi-Square Data with a
.05 level of significance, provide a summary report for the Vice
President including the following information in an essay with a
minimum of 500 words:
Two-Sample Hypothesis Test: Discuss the hypothesis test
assumptions and test used. Provide the test statistic and p-value
in your response. Evaluate the results of the hypothesis test with
the scenario. Provide recommendations for the Vice President.
Chi-square Hypothesis Test: Discuss the hypothesis test
assumptions...
Using the Sample Hypothesis Test Data and Chi-Square Data with a .05 level of significance, provide...
Using the Sample Hypothesis Test Data and Chi-Square Data with a
.05 level of significance, provide a summary report for the Vice
President including the following information:
Two-Sample Hypothesis Test: Discuss the hypothesis test
assumptions and test used. Provide the test statistic and p-value
in your response. Evaluate the results of the hypothesis test with
the scenario. Provide recommendations for the Vice President.
Chi-square Hypothesis Test: Discuss the hypothesis test
assumptions and test used. Provide the test statistic and p-value...
Using the Sample Hypothesis Test Data and Chi-Square Data with a .05 level of significance, provide...
Using the Sample Hypothesis Test Data and Chi-Square Data with a
.05 level of significance, provide a summary report including the
following information:
Two-Sample Hypothesis Test: Discuss the hypothesis test
assumptions and test used. Provide the test statistic and p-value
in your response. Evaluate the results of the hypothesis test with
the scenario.
Chi-square Hypothesis Test: Discuss the hypothesis test
assumptions and test used. Provide the test statistic and p-value
in your response. Evaluate the results of the hypothesis test...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Will iron(III) hydroxide precipitate from a pH = 1.00 solution with [Fe3+] = 1.0 x 10-5?...
- What do you believe happens during the final scene of the story between the brothers at....
- A 5.171 g sample of a solid, weak, monoprotic acid is used to make a 100.0...
- 1. Creep is one of deformation that occurred in concrete structure. Give one example that can...
- Why does a particular codon represent only one specific amino acid?
- Write a function template sort that takes two references to generic objects and switches them if...
- What 2 things happen to the melting point of a solid when an impurity is present?
ADVERTISEMENT