Question

In: Statistics and Probability

Tom Nook would like to launch an investigation to see what proportion of fish caught are...

Tom Nook would like to launch an investigation to see what proportion of fish caught are horse mackerals. What sample size would be required to do this with 95% confidence to within 0.03?

Solutions

Expert Solution

Solution :

Given that,

= 0.5

1 - = 1 - 0.5 = 0.5

margin of error = E = 0.03

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.96 / 0.03)2 * 0.5 * 0.5

= 1067.11

Sample size =1067


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