In: Statistics and Probability
D3 a product is either rectangular or triangular. What is the probability that, in a random sample of 10 units, there are more than 8 rectangular units of product? Round your answer to 4 decimal places. Assume that the population proportion of rectangular products is the same as the sample proportion of rectangular products
| Product weight (g) | Product height (mm) | Product colour | Product shape | 
| 18 | 53 | Yellow | Rectangular | 
| 11 | 93 | Yellow | Rectangular | 
| 19 | 43 | Red | Rectangular | 
| 15 | 69 | Red | Rectangular | 
| 19 | 42 | Yellow | Rectangular | 
| 11 | 78 | Red | Triangular | 
| 11 | 74 | Yellow | Rectangular | 
| 20 | 90 | Yellow | Rectangular | 
| 11 | 90 | Blue | Rectangular | 
| 11 | 84 | Yellow | Triangular | 
| 19 | 48 | Red | Triangular | 
| 13 | 56 | Blue | Triangular | 
| 20 | 79 | Blue | Rectangular | 
| 11 | 60 | Red | Rectangular | 
| 13 | 53 | Blue | Rectangular | 
| 16 | 93 | Yellow | Rectangular | 
| 16 | 91 | Yellow | Triangular | 
| 20 | 67 | Yellow | Rectangular | 
| 19 | 63 | Blue | Triangular | 
| 15 | 53 | Yellow | Rectangular | 
| 12 | 75 | Blue | Triangular | 
| 18 | 91 | Red | Rectangular | 
| 35 | 91 | Red | Triangular | 
| 25 | 93 | Red | Rectangular | 
| 30 | 44 | Yellow | Rectangular | 
The Given data is
| 
 Product weight (g)  | 
 Product height (mm)  | 
 Product colour  | 
 Product shape  | 
||
| 
 18  | 
 53  | 
 Yellow  | 
 Rectangular  | 
||
| 
 11  | 
 93  | 
 Yellow  | 
 Rectangular  | 
||
| 
 19  | 
 43  | 
 Red  | 
 Rectangular  | 
||
| 
 15  | 
 69  | 
 Red  | 
 Rectangular  | 
||
| 
 19  | 
 42  | 
 Yellow  | 
 Rectangular  | 
||
| 
 11  | 
 78  | 
 Red  | 
 Triangular  | 
||
| 
 11  | 
 74  | 
 Yellow  | 
 Rectangular  | 
||
| 
 20  | 
 90  | 
 Yellow  | 
 Rectangular  | 
||
| 
 11  | 
 90  | 
 Blue  | 
 Rectangular  | 
||
| 
 11  | 
 84  | 
 Yellow  | 
 Triangular  | 
||
| 
 19  | 
 48  | 
 Red  | 
 Triangular  | 
||
| 
 13  | 
 56  | 
 Blue  | 
 Triangular  | 
||
| 
 20  | 
 79  | 
 Blue  | 
 Rectangular  | 
||
| 
 11  | 
 60  | 
 Red  | 
 Rectangular  | 
||
| 
 13  | 
 53  | 
 Blue  | 
 Rectangular  | 
||
| 
 16  | 
 93  | 
 Yellow  | 
 Rectangular  | 
||
| 
 16  | 
 91  | 
 Yellow  | 
 Triangular  | 
||
| 
 20  | 
 67  | 
 Yellow  | 
 Rectangular  | 
||
| 
 19  | 
 63  | 
 Blue  | 
 Triangular  | 
||
| 
 15  | 
 53  | 
 Yellow  | 
 Rectangular  | 
||
| 
 12  | 
 75  | 
 Blue  | 
 Triangular  | 
||
| 
 18  | 
 91  | 
 Red  | 
 Rectangular  | 
||
| 
 35  | 
 91  | 
 Red  | 
 Triangular  | 
||
| 
 25  | 
 93  | 
 Red  | 
 Rectangular  | 
||
| 
 30  | 
 44  | 
 Yellow  | 
 Rectangular  | 
Also we know that the population proportion of rectangular products is the same as the sample proportion of rectangular products
let p be the sample proportion of rectangular products and P be the population proportion of rectangular products , the p is same as P or unbiased estimate of population parameter
Now consider p be the probability of success . Here success denoted proportion of rectangular products in given sample.
Now we are given samples of size 25 .
In sample of size 25 we have 17 recatangle products and 8 triangle products .
Thus p = 17 / 25 = 0.68
So getting an rectangular unit is binomial process with probability of success p = 0.68
i.e P (X = x ) = f(x) ~ B( n , p = 0.68 )
                 
P(X=x) =   

We need to find the probability that, in a random sample of 10 units, there are more than 8 rectangular units of product
Thus here n = 10 , p =0.68 We need to find P(X > 8 )
Now P(X>8) = P(X=9) + P(X=10)
                    
= 
+ 

                    
= 10 * 
 + 1 * 
= 0.09947872 + 0.02113923 = 0.1206179
Thus P(X>8) = 0.1206179
Hence probability that , in a random sample of 10 units , there are more than 8 rectangular of product is 0.1206179