In: Statistics and Probability
A poll asked adults in a certain country whether immigration was a good thing or a bad thing for the country. Out of 1062 respondents, 384 said it was a good thing. a. What percentage of those taking the poll said immigration was a good thing? b. Check the conditions to determine whether you can apply the CLT to find a confidence interval. c. Find a 95% confidence interval for the proportion who believe immigration is a good thing.
Solution :
n = 1062
x = 384
= x / n = 384 / 1062 =0.362
1 - = 1 - 0.362= 0.638
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z / 2 * (( * (1 - )) / n)
=1.960 * ((0.362 * 0.638 / 1062 )
= 0.029
A 95 % confidence interval for population proportion p is ,
- E < P < + E
0.362 - 0.029 < p < 0.362 + 0.029
0.333 < p < 0.391