Question

In: Computer Science

Write a computer program for a logic bomb that continually generates 8-digit numbers randomly and increases...

  1. Write a computer program for a logic bomb that continually generates 8-digit numbers randomly and increases a counter by one each time. If the random number meets the current date in a format mmddyyyy, it will display 6 times on screen the following message:

Today is [date]!

The count is: [nnnn]

Hint: Since everyday is a different date, don’t hard code the date in your program. And the [nnnn] should be the number from your counter.

Solutions

Expert Solution

1).ANSWER:

GIVEN BELOW:

import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Random;

public class GenerateRandom {

public static void main(String[] args)throws Exception {
DateFormat dateFormat = new SimpleDateFormat("MMddyyyy");//declaring the date format
Date date = new Date();//creating an object for the date
int s = Integer.parseInt(dateFormat.format(date));//converting the date from string to int
int num = 0;//initializing num
int count =0;//initializing count
Random generator = new Random();//creating an object for random class
//generator.setSeed(System.currentTimeMillis());
do{ //do while loop to iterate the loop until date equals to random number
num = generator.nextInt(9999999) + 9999999; //generating 8 digit random number
count ++;//incrementing the count
}while(s != num); //checking random number is equal to date or not
if(s == num){//if date equals to random number then
for(int i = 0;i<5; i++){ //iterate for loop to print the message 5 times
System.out.println("Today date is "+num);//display date
System.out.println("The count is "+count);//display count
System.out.println("\n");//assign one line space
}
}
}
}

output:


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