In: Statistics and Probability
People with albinism have little pigment in their skin, hair, and eyes. The gene that governs albinism has two forms (alleles), which are denoted by a and A. Each person has a pair of these genes, one inherited by from each parent. A child inherits one of each parent’s two alleles, independently with probability 0.5. Albinism is a recessive trait, so a person is albino only of the inherited pair is aa.
Hint: Make a probability tree.
Assume that the probabilities for Beth’s genetic types are given by part (c) above. Beth marries Bob who is albino.
ANSWER::
(OR)
ANSWER:
(a) Beth's parents are not albino but she has an albino brother.
This implies that both of Beth's
parents have type
Aa.Why?
Ans:Because if Beth’s parents are not albino, but she has an albino
brother (aa), then each parent must have the allele a
(b) Which of the types aa, Aa, AA could a child of Beth's
parents have? What is the probability of each type?
Ans:Since each type is equally likely, and each is inherited
independently of each other then
P(AA) = 0.5(0.5) = 1/4 ,
P(Aa) = (0.5)(0.5) + (0.5)(0.5) = 1/2, and P(aa) = 1/4.
A | a | |
A | AA | Aa |
a | aA | aa |
(c) Beth is not albino.What are the conditional probabilities
for Beth's possible genetic types, given this fact?
Ans: we can rule out aa, since Beth is not an Albino. So having
ruled out that possibility the new probabilities are:
P(AA | not aa) = 1/3. P(Aa | not aa) = 2/3.
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