In: Statistics and Probability
Consider the following hypotheses:
H0: p ≥ 0.45
HA: p < 0.45
What is the pvalue for A,B,C,and D?
a. | x = 42; n = 105 | |||
b. | x = 139; n = 331 | |||
c. | p¯ = 0.35; n = 69 | |||
d. | p¯ = 0.35; n = 456 |
a) P-Value = 0.1515
b) P-Value = 0.1358
c) P-Value = 0.0475
d) P-Value = 0
Explanation:
p= 0.45
H0: p ≥ 0.45
HA: p < 0.45
a)
x = 42; n = 105 |
Calculate test statistics
z = -1.03
P-Value = P(z < -1.03)
using normal z table we get
P(z < -1.03)= 0.1515
P-Value = 0.1515
b)
x = 139; n = 331 |
Calculate test statistics
z = -1.10
P-Value = P(z < -1.10)
using normal z table we get
P(z < -1.10)= 0.1358
P-Value = 0.1358
c)
= 0.35; n = 69
Calculate test statistics
z = -1.67
P-Value = P(z < -1.67)
using normal z table we get
P(z < -1.67)= 0.0475
P-Value = 0.0475
d)
= 0.35; n = 456
Calculate test statistics
z = -4.29
P-Value = P(z < -4.29)
using normal z table we get
P(z < -4.29 )= 0
P-Value = 0