In: Statistics and Probability
Consider the following hypotheses:
H0: p ≥ 0.48
HA: p < 0.48
Which of the following sample information enables us to reject the null hypothesis at α = 0.01 and at α = 0.05? (You may find it useful to reference the appropriate table: z table or t table) (Round all intermediate calculations to at least 4 decimal places.)
α = 0.01 | α = 0.05 | |||||||
a. | x = 32; n = 89 | (Click to select) Do not reject H0 Reject H0 | (Click to select) Do not reject H0 Reject H0 | |||||
b. | x = 123; n = 323 | (Click to select) Reject H0 Do not reject H0 | (Click to select) Reject H0 Do not reject H0 | |||||
c. | p¯ = 0.46; n = 69 | (Click to select) Do not reject H0 Reject H0 | (Click to select) Do not reject H0 Reject H0 | |||||
d. | p¯ = 0.46; n = 458 | (Click to select) Do not reject H0 Reject H0 | (Click to select) Reject H0 Do not reject H0 | |||||
Since we are comparing sample proportion with the hypothesized proportion, option (a) and (b) are incorrect.
taking option c)
The z-statistic is computed as follows,
The p-value is obtained from the z distribution table for z = -0.3325. (In excel use function =NORM.S.DIST(-0.3325,TRUE)
taking option d)
The z-statistic is,
The p-value is obtained from the z distribution table for z = -0.8567. (In excel use function =NORM.S.DIST(-0.8567,TRUE)
No sample information enables us to reject the null hypothesis at alpha = 0.05 and alpha = 0.01