In: Statistics and Probability
Last rating period, the percentages of viewers watching several
channels between 11 p.m. and 11:30 p.m. in a major TV market were
as follows:
WDUX (News) |
WWTY (News) |
WACO (Cheers Reruns) |
WTJW (News) |
Others |
16% | 19% | 24% | 16% | 25% |
Suppose that in the current rating period, a survey of 2,000
viewers gives the following frequencies:
WDUX (News) |
WWTY (News) |
WACO (Cheers Reruns) |
WTJW (News) |
Others |
335 | 495 | 444 | 378 | 348 |
(a) Show that it is appropriate to carry out a
chi-square test using these data.
Each expected value is ≥
(b) Test to determine whether the viewing shares in the current rating period differ from those in the last rating period at the .10 level of significance. (Round your answer to 3 decimal places.)
χ2χ2
(Click to select)Do not rejectReject H0. Conclude viewing shares of the current rating period (Click to select)differdo not differ from those of the last.
a)
each expected value ≥ 5
b)
Chi square test for Goodness of fit
expected frequncy,E = expected proportions*total
frequency
total frequency= 2000
category | observed frequencey, O | expected proportion | expected frequency,E | (O-E)²/E | ||
WDUX | 335 | 0.1600 | 320 | 0.703 | ||
WWTY | 495 | 0.1900 | 380 | 34.803 | ||
WACO | 444 | 0.2400 | 480 | 2.700 | ||
WTJM | 378 | 0.1600 | 320 | 10.513 | ||
others | 348 | 0.2500 | 500 | 46.208 |
chi square test statistic,X² = Σ(O-E)²/E =
94.926
level of significance, α= 0.1
Degree of freedom=k-1= 5 -
1 = 4
P value = 0.0000 [ excel function:
=chisq.dist.rt(test-stat,df) ]
Decision: P value < α, Reject Ho
conclusion: Reject H0. Conclude viewing shares of the current rating period