In: Statistics and Probability
7(B) The weight of an average footballer in team A is 220lbs. The standard deviation is 15lbs. A coach scouting a sample of 4 footballers will sign them if the sample mean weight is less than 215lbs.
Solution :
Given that ,
mean = = 220
standard deviation = = 15
(A)n = 4
= 220
= / n = 15/ 4=7.5
P( < 215) = P[( - ) / < (215 -220) / 7.5]
= P(z < -0.67)
Using z table
= 0.2514
probability=0.2514
(B)
n = 100
= 220
= / n = 15/ 100=1.5
P( < 215) = P[( - ) / < (215 -220) / 1.5]
= P(z < -3.33)
Using z table
= 0.0004
probability=0.0004