Question

In: Statistics and Probability

15-6: Consider the following set of data: x1              10        8          11    &nbs

15-6: Consider the following set of data:

x1              10        8          11        7          10        11            6

x2         50        45        37        32        44        51            42

y          103      85        115      73        97        102            65

  1. Obtain the estimate regression equation.

  1. Examine the coefficient of determination and the adjusted of determination. Does it seem that either of the independent variables’ addition to R2 does not justify the reduction in degrees of freedom that results from its addition to the regression model? Support your assertions.

  1. Conduct a hypothesis test to determine if the dependent variable increases when x2 increases. Use a significance level of 0.025 and the p-value approach.

  1. Construct a 95% confidence interval for the coefficient of x1.

Solutions

Expert Solution

(a) The estimate regression equation is:

y = 21.0426 + 9.0383*x1 - 0.2549*x2

(b) The coefficient of determination and the adjusted of determination are 0.951 and 0.926 respectively. Yes, independent variables does not justify the reduction in degrees of freedom that results from its addition to the regression model becuase we take the pair of data in regression.

(c) The hypothesis being tested is:

H0: β2 = 0

H1: β2 ≠ 0

The p-value from the output is 0.4754.

Since the p-value (0.4754) is greater than the significance level (0.05), we cannot reject the null hypothesis.

Therefore, we cannot conclude that the dependent variable increases when x2 increases.

(d) The 95% confidence interval for the coefficient of x1 is between 5.9882 and 12.0885.

0.951
Adjusted R² 0.926
R   0.975
Std. Error   4.859
n   7
k   2
Dep. Var. y
ANOVA table
Source SS   df   MS F p-value
Regression 1,817.2788 2   908.6394 38.49 .0024
Residual 94.4355 4   23.6089
Total 1,911.7143 6  
Regression output confidence interval
variables coefficients std. error    t (df=4) p-value 95% lower 95% upper
Intercept 21.0426
x1 9.0383 1.0986 8.227 .0012 5.9882 12.0885
x2 -0.2549 0.3240 -0.787 .4754 -1.1543 0.6446

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