In: Statistics and Probability
15-6: Consider the following set of data:
x1 10 8 11 7 10 11 6
x2 50 45 37 32 44 51 42
y 103 85 115 73 97 102 65
(a) The estimate regression equation is:
y = 21.0426 + 9.0383*x1 - 0.2549*x2
(b) The coefficient of determination and the adjusted of determination are 0.951 and 0.926 respectively. Yes, independent variables does not justify the reduction in degrees of freedom that results from its addition to the regression model becuase we take the pair of data in regression.
(c) The hypothesis being tested is:
H0: β2 = 0
H1: β2 ≠ 0
The p-value from the output is 0.4754.
Since the p-value (0.4754) is greater than the significance level (0.05), we cannot reject the null hypothesis.
Therefore, we cannot conclude that the dependent variable increases when x2 increases.
(d) The 95% confidence interval for the coefficient of x1 is between 5.9882 and 12.0885.
R² | 0.951 | |||||
Adjusted R² | 0.926 | |||||
R | 0.975 | |||||
Std. Error | 4.859 | |||||
n | 7 | |||||
k | 2 | |||||
Dep. Var. | y | |||||
ANOVA table | ||||||
Source | SS | df | MS | F | p-value | |
Regression | 1,817.2788 | 2 | 908.6394 | 38.49 | .0024 | |
Residual | 94.4355 | 4 | 23.6089 | |||
Total | 1,911.7143 | 6 | ||||
Regression output | confidence interval | |||||
variables | coefficients | std. error | t (df=4) | p-value | 95% lower | 95% upper |
Intercept | 21.0426 | |||||
x1 | 9.0383 | 1.0986 | 8.227 | .0012 | 5.9882 | 12.0885 |
x2 | -0.2549 | 0.3240 | -0.787 | .4754 | -1.1543 | 0.6446 |