Question

In: Statistics and Probability

In this lab we will test to see if there is evidence of a difference in...

In this lab we will test to see if there is evidence of a difference in the average age for at least 1 of 4 groups

of marital status (i.e., single, married, divorced, widowed). Use ?= 0.05.

ANOVA

Age in Years  

Sum of Squares

df

Mean Square

F

Sig.

Between Groups

8993.608

3

2997.869

25.214

.000

Within Groups

11414.182

96

118.898

Total

20407.790

99

To include in your submission:

ü Copy the ANOVA Table from the SPSS output to your Word document. Please make sure to adjust the

size of your tables so that they fit on the page.

ü Using the ANOVA table, answer the following for the one-way ANOVA:

a. Type the hypotheses.

b. Type in the test statistic found from the SPSS output.

c. Type in the p-value found from the SPSS output.

d. Type your decision regarding the null hypothesis.

e. Type in your conclusion using context and units from the problem

Solutions

Expert Solution

Solution:

Given:

ANOVA
Age in Years  
Sum of Squares df Mean Square F Sig.
Between Groups 8993.608 3 2997.869 25.214 0.000
Within Groups 11414.182 96 118.898
Total 20407.79 99

We have to test if there is evidence of a difference in the average age for at least 1 of 4 groups of marital status (i.e., single, married, divorced, widowed).

Level of Significance = 0.05

Part a) Type the hypotheses.

H0: the average age for 4 groups of marital status (i.e., single, married, divorced, widowed) is equal.

( That is: )

Vs

H1: the average age for at least 1 of 4 groups of marital status (i.e., single, married, divorced, widowed) is different.

Part b) Type in the test statistic found from the SPSS output.

F is the test statistic.

We have F test statistic: F = 25.214

Part c) Type in the p-value found from the SPSS output.

Value under Sig. column is nothing p-value.

Thus p-value = 0.000

Part d) Type your decision regarding the null hypothesis.

Decision Rule:
Reject H0, if p-value < 0.05 level of significance, otherwise we fail to reject H0

Since  p-value = 0.000 < 0.05 level of significance, we reject null hypothesis H0.

Part e) Type in your conclusion using context and units from the problem

At  0.05 level of significance, there is sufficient evidence of a difference in the average age for at least 1 of 4 groups of marital status (i.e., single, married, divorced, widowed).


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