In: Statistics and Probability
a) You choose 3 babies at random. What is the probability that their average birth weight is less than 5.5 pounds?
b) What is the third quartile of the distribution?
Solution :
Given that,
mean = = 7.5
standard deviation = = 1.25
n = 3
= 7.5
= / n = 1.25/ 3=0.72
a.
P( <5.5 ) = P[( - ) / < (5.5-7.5) /0.72 ]
= P(z < -2.78)
Using z table
= 0.0027
probability= 0.0027
b.
Using standard normal table,
P(Z < z) = 75%( third quartile)
= P(Z < z) = 0.75
= P(Z < 0.67) = 0.75
z = 0.67 Using standard normal table,
Using z-score formula
= z * +
=0.67*0.72+7.5
= 7.98