The ΔH°rxn for the following reaction is −114.2 kJ/mol. At what temperature (in °C) would the...

The ΔH°rxn for the following reaction is −114.2 kJ/mol. At what temperature (in °C) would the Kc for the reaction be 6.4 x 109? 2NO(g) + O2(g) ↔ 2NO2(g) Kc = 4.9 x 105 at 184°C

271°C

183°C

110°C

74°C

Expert Solution

T1 = 184⁰C = 184 + 273 = 457K

logK2/K1 = H/2.303R [1/T2 -1/T1]

log6.4*10^9/4.9*10^5 = -114200/2.303*8.314 [1/T2 -1/457]

log13061.22 = -5964.34[1/T2-0.00218]

4.1159 /-5964.34 = [1/T2-0.00218]

-0.00069 = 1/T2-0.00218

-0.00069+0.00218 = 1/T2

1/T2 = 0.00149

T2 = 671K = 671-273 = 398⁰C >>>>>answer

queen_honey_blossom answered 2 years ago

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