In: Statistics and Probability
Starting salaries of 64 college graduates who have taken a statistics course have a mean of $44,500 with a standard deviation of $6,800. Find a 99.7% confidence interval for ?. (NOTE: Do not use commas or dollar signs in your answers. Round each bound to three decimal places.)
Lower-bound: Upper-bound:
Solution :
Given that,
t /2,df = 3.087
Margin of error = E = t/2,df * (s /n)
= 3.087 * (6800 / 64)
Margin of error = E = 2623.950
The 99.7% confidence interval estimate of the population mean is,
- E < < + E
44500 - 2623.950 < < 44500 + 2623.950
41876.050 < < 47123.950
Lower-bound: 41876.050
Upper-bound: 47123.950