Question

For the reaction

2KClO3(s)→2KCl(s)+3O2(g)

calculate how many grams of oxygen form when each quantity of reactant completely reacts.

A. 2.01 gKClO3

B. 0.301 gKClO3

C. 88.7 kgKClO3

D.25.1 mgKClO3

Answer 1

2 KClO3 (s)   ----------------> 2 KCl (s) + 3 O2(g)

A)

2 KClO3 (s)   ----------------> 2 KCl (s) + 3 O2(g)

245.1 g                                                    96 g

2.01 g                                                        ??

mass of Oxygen formed = 2.01 x 96 / 245.1

mass of Oxygen formed = 0.787 g

B)

2 KClO3 (s)   ----------------> 2 KCl (s) + 3 O2(g)

245.1 g                                                    96 g

0.301 g                                                        ??

mass of Oxygen formed = 0.301 x 96 / 245.1

mass of Oxygen formed = 0.118 g

C)

2 KClO3 (s)   ----------------> 2 KCl (s) + 3 O2(g)

245.1 g                                                    96 g

88700 g                                                        ??

mass of Oxygen formed = 88700 x 96 / 245.1

mass of Oxygen formed = 3.47 x 10^4 g

D)

mass of Oxygen formed = 9.83 x 10^-3 g