Question

In: Statistics and Probability

An airport shuttle service wants to determine the length of time it would take to transport...

An airport shuttle service wants to determine the length of time it would take to transport passengers from various locations to a major metropolitan airport during nonpeak hours. A sample of 16 trips on a particular day during nonpeak hours indicates the following:

Distance (miles)

Time (minutes)

Distance (miles)

Time (minutes)

35.0

29

15.7

41

19.5

35

18.4

27

25.4

70

20.2

37

27.0

55

21.8

36

10.3

19

24.3

40

11.6

18

30.3

21

16.1

23

9.2

20

14.3

40

12.1

24

  1. Using Excel, create a scatter diagram for distance and time. This what should be your Y (dependent) variable and what should be your X (independent) variable. No need to submit the results.

  2. Calculate the covariance between distance and time using Excel. What is its value?

  3. Calculate the correlation coefficient. What is its value?

  4. Calculate the least-squares regression equation using distance as an independent variable and time as a dependent variable______ Intercept:_____

  5. Is the intercept coefficient significant at the 5% level? Yes or No?

  6. Is the slope coefficient significant at the 5% level? Yes or No?


Solutions

Expert Solution

a) A scatter diagram for distance and time.

Distance(X) Time(Y) (y-ybar)^2 (x-xbar)^2 (x-xbar)(y-ybar)
35 29 19.7136 241.8025 -69.042
19.5 35 2.4336 0.0025 0.078
25.4 70 1336.6336 35.4025 217.532
27 55 464.8336 57.0025 162.778
10.3 19 208.5136 83.7225 132.126
11.6 18 238.3936 61.6225 121.204
16.1 23 108.9936 11.2225 34.974
14.3 40 43.0336 26.5225 -33.784
15.7 41 57.1536 14.0625 -28.35
18.4 27 41.4736 1.1025 6.762
20.2 37 12.6736 0.5625 2.67
21.8 36 6.5536 5.5225 6.016
24.3 40 43.0336 23.5225 31.816
30.3 21 154.7536 117.7225 -134.974
9.2 20 180.6336 105.0625 137.76
12.1 24 89.1136 54.0225 69.384
311.2 535 3007.9376 838.88 656.95
19.45 33.44

b) The covariance between distance and time is given by,

= 656.95 / 16 [ from the table above]

= 41.059

c)  The correlation coefficient is given by,

  

= 0.413

d) the least-squares regression equation using distance as an independent variable and time as a dependent variable

b = 656.95 / 838.88 = 0.783, Slope

a = 33.44 - 0.783*19.45 = 18.211, Intercept

y = 18.211 + 0.783 x

Distancex Timey yhat (y-yhat)^2
35 29 45.616 276.0915
19.5 35 33.4795 2.31192
25.4 70 38.0992 1017.661
27 55 39.352 244.8599
10.3 19 26.2759 52.93872
11.6 18 27.2938 86.37472
16.1 23 30.8173 61.11018
14.3 40 29.4079 112.1926
15.7 41 30.5041 110.1639
18.4 27 32.6182 31.56417
20.2 37 34.0276 8.835162
21.8 36 35.2804 0.517824
24.3 40 37.2379 7.629196
30.3 21 41.9359 438.3119
9.2 20 25.4146 29.31789
12.1 24 27.6853 13.58144
311.2 535 535.0456 2493.462

SSE = 2493.462

e) test statistic of intercept is given by,

  

t = 0.51

p-vaue = 0.6175 > 0.05

No, at level 0.05, intercept coefficient is not significant.

f) test statistic of slope coefficient is given by,

  

t = 1.70

p-value = 0.1098 < 0.05

No, at level 0.05, slope coefficient is not significant.

*****If you have any queries or doubts please comment below, if you're satisfied please give a like. Thank you!


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