Question

In: Statistics and Probability

The mean caloric intake of an adult male is 2800 with a standard deviation of 115....

The mean caloric intake of an adult male is 2800 with a standard deviation of 115. To verify this information, a sample of 25 men are selected and determined to have a mean caloric intake of 2950. Determine the 98% confidence interval for mean caloric intake of an adult male.

Solution:

Since n < 30, a t-test must be used.

2950 – qt(1.98/2,24)*115/sqrt(25)

2950 + qt(1.98/2,24)*115/sqrt(25)

[2892.68, 3007.32]

What is wrong with this solution?

Solutions

Expert Solution

This answer is totally correct.we can check it by manually as well as using Minitab software.

Using Minitab software we get output ,

Thank You!

orchestra answered 1 year ago
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