The mean caloric intake of an adult male is 2800 with a standard deviation of 115....

The mean caloric intake of an adult male is 2800 with a standard deviation of 115. To verify this information, a sample of 25 men are selected and determined to have a mean caloric intake of 2950. Determine the 98% confidence interval for mean caloric intake of an adult male.

Solution:

Since n < 30, a t-test must be used.

2950 – qt(1.98/2,24)*115/sqrt(25)

2950 + qt(1.98/2,24)*115/sqrt(25)

[2892.68, 3007.32]

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Expert Solution

This answer is totally correct.we can check it by manually as well as using Minitab software.

Using Minitab software we get output ,

Thank You!

orchestra answered 1 year ago

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