Question
In: Statistics and Probability
The mean caloric intake of an adult male is 2800 with a standard deviation of 115....
The mean caloric intake of an adult male is 2800 with a standard deviation of 115. To verify this information, a sample of 25 men are selected and determined to have a mean caloric intake of 2950. Determine the 98% confidence interval for mean caloric intake of an adult male.
Solution:
Since n < 30, a t-test must be used.
2950 – qt(1.98/2,24)*115/sqrt(25)
2950 + qt(1.98/2,24)*115/sqrt(25)
[2892.68, 3007.32]
What is wrong with this solution?
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Expert Solution
This answer is totally correct.we can check it by manually as well as using Minitab software.
Using Minitab software we get output ,
Thank You!
orchestra answered 1 year agoRelated Solutions
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